選擇與重覆<題目9：Roller Coaster (104-1 Mid-term 1)>

程式說明

艾莉要設計一座雲霄飛車的軌道，為了評估軌道的安全性，她將計算軌道高度變化量的平均值；如果平均變化量高於5，就被認為是太過危險而不能接受。



以五段的雲霄飛車為例，包含起點和終點共有六個端點，其高度為 0, 10, 7, 5, 9, 0，則高度變化量為10, 3, 2, 4, 9，平均為 (10+3+2+4+9)/5 = 28/5 > 5，因此無法接受。



本題將輸入一串以 0 開始，以 0 結束的整數值（起點和終點的高度必為 0），代表雲霄飛車軌道端點的高度。請輸出軌道的平均高度差，並判斷是否可接受（> 5 即不可接受）。輸出格式請參照以下範例。



輸入範例一

0 10 7 5 9 0

輸出範例一

Average 28/5 is not accepted.

輸入範例二

0 0

輸出範例二

Average 0/1 is accepted.

輸入範例三

0 1 2 3 0

輸出範例三

Average 6/4 is accepted.

***以下為參考程式***（注意!!複製貼上此程式碼，將對你沒好處）

#include <stdio.h>



int main()

{

    int began = 0 , H = 0 , total = 0 , change = 0 , time = 1 ;

    float ave = 0 ;



    scanf("%d", &began );



    while ( 1 )
    {

        scanf("%d", &H );


    
        if( H == 0 )

        {

            if( H >= began )

            {

                change = H - began;

                began = H;

            }

            else

            {

                change = began - H;

                began = H;

            }

            total = total + change;

            break;

        }

        else

        {

            if( H >= began )

            {

                change = H - began;

                began = H;

            }

            else

            {

                change = began - H;

                began = H;

            }

            total = total + change;

            time++;

        }

    }    

    ave = (float)total / time;

    if( ave > 5 )

    {

        printf("Average %d/%d is not accepted.", total , time );

    }

    else

    {

        printf("Average %d/%d is accepted.", total , time );

    }

    return 0;

}